Additional Maths

Yesterday, amazingly, I did 3 A Math papers in a row.

I worked from about 9 to about 12 probably, so 3 hours for 3 papers is quite good. There's one question which I think is screwed up though.

It asks: What is the definite integral, from 3 to 0, of 1/(1-3x)^2.

The paper claims the answer is -3/8. But I think the answer should be undefined, because at x = 1/3 which is within the range, the function is undefined. In other words, the function is not continuous over the range 3 to 0.

What I did just to confirm...